The sum of three fractions is 2(11 / 24). When the largest fraction is divided by the smallest, the fraction thus obtained is 7 / 6 which is 1 / 3 more than the middle one. The fractions are :

a. 3 / 5, 4 / 7, 2 / 3
b. 7 / 8, 5 / 6, 3 / 4
c. 7 / 9, 2 / 3, 3 / 5
d. None of these

• By option we got
  a. 3/5+4/7+2/3=193/105=1(88/105)
  b.7/8+5/6+3/4=472/192=2(11/24)
  c.7/9+2/3+3/5=92/45=2(2/45)
  
  So we got from option b the given value
  But when we divide largest fraction to the smallest we got 1/8
  
  So option d none of these is the correct answer.
  
  =
• 8 years agoHelpfull: Yes(0) No(1)
• As option b have sum of fraction is 2(11/24)
  When7/8 is divided by 3/4,it is =7/6
  7/6-5/6=1/3
  Thus , 1/3 is more than middle one
  So b is the correct answer
• 8 years agoHelpfull: Yes(0) No(0)
• is's answer is b
  let a, b ,c are three fractions
  a+b+c=59/24
  and b=7/6 - 1/3
  so b= 5/6
  and one more eq. is a/c=7/6
  so on solving first and this c=3/4
  and a = 7/8
• 8 years agoHelpfull: Yes(0) No(0)