A pizza shop, there were 2 kinds of pizzas available. But now they have introduces 8 new types, a person buy two different type pizzas of new type in how many ways he can select?
option
(a) 24
(b) 43
(c) 56
(d) 58

• 8*7=56
• 14 years agoHelpfull: Yes(6) No(4)
• none of these...
  because ans is 8c2=28
• 14 years agoHelpfull: Yes(5) No(5)
• here it is aselection process .so we have to consider combintation.
  then selecting 2 from 8 verities is 8c2=(8*7)/2=28.so none of the above
• 14 years agoHelpfull: Yes(5) No(4)
• simply 8c2 way..and 8c2 gives result (8!/6!*2!)=28
• 14 years agoHelpfull: Yes(5) No(6)
• hey guys its not combination problem.its a permutation probem.the correct solution for this question is 8P2.and the formula for 8P2 is
  8!/(8-2)!=
  8*7*6!/6!=
  8*7=56
  this is the correct solution for the question.....
• 14 years agoHelpfull: Yes(5) No(3)
• 8c2 ways
• 14 years agoHelpfull: Yes(4) No(4)
• 8p2
• 14 years agoHelpfull: Yes(2) No(5)
• we need to select 2 different pizzas from 8
  1st pizza from 8 is 8c1
  2nd pizza from 7 is 7c1
  (without replacement)
  so 7c1 * 8c1 = 56
• 10 years agoHelpfull: Yes(2) No(0)
• first tere are 2 kinds of pizza.Addition to tat 8 different types.So totally 10 pizza flavour.In order to select 2 pizza kinds out of 10 is 10c2..
  10c2-2=45-2=43.....option b
• 14 years agoHelpfull: Yes(1) No(6)
• 8C2 ways
  
  8c2=8*7=56
• 14 years agoHelpfull: Yes(0) No(11)
• we need to select 2 different pizzas from 8
  1st pizza from 8 is 8c1
  2nd pizza from 7 is 7c1
  (without replacement)
  so 7c1 * 8c1 = 56
  
• 10 years agoHelpfull: Yes(0) No(0)