If the digits of my present age are reversed then i get the age of my son. If 1 year ago my age was twice as that of my son. Find my present age.

• let fathers age be 10x+y and sons age be 10y+x
  so
  10x+y-1=2(10y+x-1)
  x=(19y-1)/8
  put the values of x=1,2,3,4,5,,6,7
  so at x=7 y=3
  hence fathers age is 73 and sons age is 37
• 10 years agoHelpfull: Yes(14) No(0)
• 10x+y = xy
  ex: 10 * 7 + 3 = 73 like this priya
  in given pblm interchanging age of father means father age must be having in the form of 2 digit
  i.e we are taking like that
• 10 years agoHelpfull: Yes(4) No(1)
• do options verification
  
• 10 years agoHelpfull: Yes(3) No(1)
• praveen how 10x+y ??
• 10 years agoHelpfull: Yes(3) No(0)
• getting solution from the choice will be easy..provide options for it
• 10 years agoHelpfull: Yes(2) No(3)
• can u pls explain how it is solved
  
• 10 years agoHelpfull: Yes(2) No(3)
• My age : 10x+y
  Son age : 10y+x
  
  so 10x+y = 10y+x
  10x+y-1 = 2(10y+x-1)
  x = (19y-1)/8
  
  for y=3
  (19y-1) is completely divisible by 8
  so x = 7
  
  So my present age : 10*7+3 = 73
  son's age : 10*3+7 = 37
• 4 years agoHelpfull: Yes(0) No(0)