Monika purchased a pressure cooker at 9/10th of its selling price and sold it at 8% more than its S.P., Her gain is :

a. 20%
b. 18%
c. 10%
d. 8 %

• S.p.=108x/100
  c.p.=9x/10
  gain=s.p-c.p=18%
  ans=b.18%
• 4 years agoHelpfull: Yes(1) No(2)
• Let the S.P of the cooker be100 Rs.
  He purchased it in 100×9/10=90 Rs
  He sold it in100×(100+8)/100=108 Rs
  Hence the gain is 108-90=18Rs.
  The gain percent is (18/90)×100=20%
• 4 years agoHelpfull: Yes(1) No(0)
• 
  (A) 20%
  Let the s.p be Rs. X .then C.P = Rs.9x/10,
  
  Receipt=108% of Rs. x=Rs 27x/25
  
  Gain=Rs (27x/25*9x/10) =Rs (108x-90x/100) =Rs18x/100
  
  Gain %=( 18x/100*10/9x*100) %=20%
  
  
  
  
  
• 8 years agoHelpfull: Yes(0) No(5)
• Monika purchased the cooker for 9/10th of S.P
  We don't know the S.P
  So let the S.P be X and she bought it for 9/10 of S.P
  Therefore the C.P be 9/10 X.
  Now she sold the cooker at 8% more than S.P
  Therefore S.P=108/100 X
  WKT % gain ={S.P - C.P/C.P}*100
• 6 years agoHelpfull: Yes(0) No(0)