The average of first five multiples of 3 is :

a. 3
b. 9
c. 12
d. 15

• Sum=n(n+1)/2
  =(3+6+9+12+15)/5
  =45/5
  =9
• 12 years agoHelpfull: Yes(3) No(5)
• B) ans
  (3+6+9+15+21)/5=9
• 9 years agoHelpfull: Yes(1) No(0)
• 3,6,9,12,15
  As they are arithmetic progression and 5 terms
  the 3rd term is average
  Or first+last/2
  3+12/2 = 9
• 9 years agoHelpfull: Yes(1) No(0)
• (3+6+9+12+15)/5=45/5=9;
• 9 years agoHelpfull: Yes(0) No(0)
• 3+6+9+12+15/5=9
• 9 years agoHelpfull: Yes(0) No(0)
• AVG OF CONSECUTIVE NUMBERS IS THE MIDDLE NUMBER (IF NUMBER OF TERMS IS ODD)
  AVG OF CONSECUTIVE NUMBERS IS THE AVG OF MIDDLE NUMBERS (IF NUMBER OF TERMS IS EVEN)
  GIVEN 3(1,2,3,4,5)
  AVG OF 1,2,3,4,5 IS 3
  ANS =3*AVG=3*3*=9
  
• 9 years agoHelpfull: Yes(0) No(0)
• the average of odd number consecutive series is its middle number i.e; 9
• 9 years agoHelpfull: Yes(0) No(0)
• first five =n(n+1)/2
  first five no=5*6/2=15
  but avg=15/5=3
• 9 years agoHelpfull: Yes(0) No(1)
• First 5 average of 3 are 3,6,9,12,15 further average is equal to sum of all numbers over total number.3+6+9+12+15÷5=9
• 6 years agoHelpfull: Yes(0) No(0)