Elitmus
Exam
Numerical Ability
Permutation and Combination
1/m+4/n=1/12
Where n is an odd integer less than 60 ??
A. 4
B. 7
C. 5
D. 3
Read Solution (Total 3)
-
- 1/m + 4/n = 1/12
Since we know something about n, so express m as the value of n.
=> 1/m = 1/12 - 4/n
=> 1/m = (n-48)/(12*n)
=> m = (12*n)/(n-48)
Now since n is odd +ve integers less than 60.
So, n must be greater than 48 so than value of m is +ve.
So range of n is: [49, 59] and only odd numbers.
Hence, n can be: (49,51,53,55,57,59)
From here we can see clearly that for n = 49, 51 and 57, we get positive integer value for m.
So there are 3 possible values for pair (m,n) - 10 years agoHelpfull: Yes(31) No(0)
- Since m and n are positive, n should be greater than 48 ( so that m is positive). So n can be 49, 51, 53, 55, 57, 59.
Let us take each values :
n = 49, m = 12 * 49/1 Both m & n are positive and integers.
n = 51, m = 12 * 51/3 Both m & n are positive and integers.
n = 53, m = 12 * 53/5 Both m & n are positive but m is not an integer.
n = 55, m = 12 * 55/7 Both m & n are positive but m is not an integer.
n = 57, m = 12 * 57/9 Both m & n are positive and integers.
n = 59, m = 12 * 59/11 Both m & n are positive but m is not an integer. - 10 years agoHelpfull: Yes(8) No(6)
- answer D
n is inter and =48.
now for n=48, m=0
for n=52, m=12*13
for n=56, m= 12*7
so only three whole value of m are possible. - 10 years agoHelpfull: Yes(4) No(1)
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