A and B play a game between them. The dice consist of colors on their faces(instead of number). When the dice are thrown, A wins if both show the same color, otherwise B wins. One die has 3 red faces and 3 blue faces. How many red and blue faces should the other die have if the both players have if the both players have the same chances of winning?
a) 5 red and 1 blue faces.
b) 1 red and 5 blue faces.
c) 3 red and 3 blue faces.

• option c
• 13 years agoHelpfull: Yes(5) No(11)
• According to the question,
  For both of them to have an equal chance of winning,
  The probability that a single color pops up on the two dice should be half
  So, Probability (dice 1 is red AND dice 2 is red) + Probability (dice 1 is blue AND dice 2 is blue) = 1/2
  Let the other dice have x red faces
  So, it will have 6-x blue faces
  So,
  (1/2)*(x/6) + (1/2)*(6-x)/6 = 1/2
  it is true for any value of x
  
• 13 years agoHelpfull: Yes(3) No(9)