The mean temperature of Monday to Wednesday was 37°C and of Tuesday to Thursday was 34°C. If the temperature on Thursday was 4 / 5th that of Monday, the tempearture on Thursday was :

a. 36.5°C
b. 36°C
c. 35.5°C
d. 34°C

• (Mon+Tue+Wed)/3=370==>Mon+Tue+Wed=1110 eqn 1
  (Tue+Wed+Thu)/3=340==>Tue+Wed+Thu=1020 eqn 2
  On subtraction Mon+Thu=90....
  As we know that Thu=(4/5)Mon ....
  On solving we will get answer as 360
• 11 years agoHelpfull: Yes(10) No(4)
• Let the temperature of Monday, Tuesday, Wednesday be x degree celsius, y degree celsius and z degree celsius respectively
  The temperature of Thursday is 4/5 * x degree celsius
  The average of the temperatures of Monday, Tuesday, Wednesday gives us
  (x +y + z)/3 = 37
  
  The average of the temperatures of Tuesday, Wednesday, Thursday gives us
  (y + z + 4/5 x) /3= 34
  
  We get
  (x +y + z) = 37 * 3
  y + z = (37 * 3) -x
  using the value of y+z in the second equation we get
  (37 * 3) -x + 4/5 x = 34 *3
  (37 * 3) – (34 * 3) = x – 4/5 x
  3 ( 37-34) = 1/5x
  9= 1/5 x
  x = 45
  
  The temperature on Monday is 45 degree celsius
  The temperature on Thursday is 4/5x = 4/5 * 45 = 36 degree celsius
• 9 years agoHelpfull: Yes(4) No(0)
• 36 degree
  m+t+w=111
  T+W+T=102
  T+W+4/5M=102
  solve the equation m=45
  thursday is 4/5*45=36 answer
• 9 years agoHelpfull: Yes(1) No(0)
• let temperature on monday be t Celsius
  On replacing monday with thrusday we got a decerease of 3 celsius on average
  therefore total change of 9 celsius
  so the temperature of thrusday will be (t - 9) celsius
  
  as per question (t - 9)=4/5*t
  therefore t=45
  and temperature on monday will be (t - 9)=36 degree
• 4 years agoHelpfull: Yes(0) No(0)