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Numerical Ability
Averages
Three years ago, the average age of A, B and C was 27 years and that of B and C, 5 years ago was 20 years. A's present age is :
a. 30 yrs
b. 35 yrs
c. 40 yrs
d. 48 yrs
Read Solution (Total 3)
-
- Option C.40
- 10 years agoHelpfull: Yes(0) No(0)
- Ans: C 40yrs
Let present ages of be A,B,C
Before three years their ages were A-3,B-3,C-3 respectively
Given
(A-3+B-3+C-3)/3 = 27
A+B+C=90
Then (B-5+C-5)/2=20
B+C=50
A=90-(B+C)
A=90-50
A=40 - 10 years agoHelpfull: Yes(0) No(0)
- total age of a,b,c at present is 27*3 + 9 =90.
total age of b,c at present is 20*2 + 10 = 50.
so the present age of a is 90 - 50 = 40. - 5 years agoHelpfull: Yes(0) No(0)
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