In an examination, A got 10% marks less than B, B got 25% marks more than C and C got 20% less than D. If A got 360 marks out of 500. The percentage of marks obtained by D was :

a. 70%
b. 75%
c. 80%
d. 85%

• A got 369/500 * 100 = 72%
  This was 90% of B. So B = 72 * 100 / 90 = 80%.
  
  This was 125% of C. So C = 80 * 100 / 125 = 64%.
  
  This was 80% of D. So D = 64 * 100 / 80 = 80%.
  So D got 80% marks.
• 10 years agoHelpfull: Yes(8) No(0)
• option(C)
  let D's mark be 100....C-->20% less than D=80
  B-->25% more than C=100
  A-->10% less than B=90
  now when A's marks is 90 then D's marks=100
  so, when A's mark is 360 then D's marks=100*360/90=400(out of 500)
  hence 80%
• 9 years agoHelpfull: Yes(5) No(1)
• the ans is 71.28%
  
• 10 years agoHelpfull: Yes(1) No(5)
• Answer is C. 80%
• 9 years agoHelpfull: Yes(1) No(1)
• d=375 =75%
  
• 9 years agoHelpfull: Yes(0) No(0)
• x=4/5
  D=100*4/5=80
  
  
  
• 9 years agoHelpfull: Yes(0) No(1)
• A got 369/500 * 100 = 72%
  This was 90% of B. So B = 72 * 100 / 90 = 80%.
  
  This was 125% of C. So C = 80 * 100 / 125 = 64%.
  
  This was 80% of D. So D = 64 * 100 / 80 = 80%.
  So D got 80% marks.
  
• 9 years agoHelpfull: Yes(0) No(0)
• Let % of marks obtained by D is x.
  % marks of C is 0.8x, % marks of B is 0.6x and % marks of A is 0.9x.
  It is given that 0.9x = 360 solving for x we get x = 80%.
  so option C is correct.
• 8 years agoHelpfull: Yes(0) No(1)
• 80%
  let d=100
  c=20% less tha d=80
  b=25%more than c=80+20
  b=100
  a=10% less tham b
  a=90
  if 90->360 then
  100->400
  80%500 is 400
• 5 years agoHelpfull: Yes(0) No(0)