In a certain office, 72% of the workers prefer tea and 44% prefer coffee. If each of them prefers tea or coffee and 40 like both, the total number of workres in the office is :

a. 200
b. 240
c. 250
d. 320

• Answer : (c) 250.
  If the total no.of workers is 100 then 72 prefer tea and 44 prefer coffee.
  n(Tea U Coffee) = n(Tea)+ n(Coffee) - n (Tea ^ Coffee)
  100 = 72 + 44 - x (x: is workers who take both coffee and tea)
  x = 116 - 100 = 16.
  Therefore Out of 100 workers, 16 take both coffee and tea.
  But as per the problem 40 take both coffee and tea
  
  100 --- 16
  ? ----- 40
  (40/16) * 100 = 250.
• 13 years agoHelpfull: Yes(15) No(1)
• those who not prefer both are =x-40
  not prefer tea =100-72 = 28%
  not prefer cofee = 100-44 = 56%
  so total=84%
  84% of x =x-40
  40 = .16x
  x=250
• 7 years agoHelpfull: Yes(1) No(0)
• Ans:
  250
  
  
  (72%+44%)−100%=16%
  16%=40
  100%=40×100 /16 =250
• 7 years agoHelpfull: Yes(1) No(0)