The length of a rectangle is increased by 60%. By what percent would the width have to be decreased to maintain the same area ?

a. 37(1 / 2)%
b. 60%
c. 75%
d. None

• assume initially l=100 and b=100
  so area =l*b
  160(100-b)=100*100
  b=37(1/2)%
• 11 years agoHelpfull: Yes(5) No(1)
• 100---------->(60% inc) 160
  
  so, (60/160)*100
  
• 8 years agoHelpfull: Yes(0) No(0)
• a.37(1/2)%
• 7 years agoHelpfull: Yes(0) No(0)
• option a is the correct ans
• 6 years agoHelpfull: Yes(0) No(0)