The length of a rectangle is increased by 60%. By what percent would the width have to be decreased to maintain the same area ?

a. 37(1 / 2)%
b. 60%
c. 75%
d. None

• assume initially l=100 and b=100
  so area =l*b
  160(100-b)=100*100
  b=37(1/2)%
• 10 years agoHelpfull: Yes(5) No(1)
• 100---------->(60% inc) 160
  
  so, (60/160)*100
  
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• a.37(1/2)%
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• option a is the correct ans
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