The radius of a sphere is increased by 50%. The increase in surface area of the sphere is :

a. 100%
b. 125%
c. 150%
d. 200%

• ANS:-125%,take radius 100. then surface area is 4*22/7*100*100.
  after increase radius by 50% the radius become 100+50% of 100=150,then new surface area is 4*22/7*150*150
  then put the values into formula of percentage((4*22/7)*150*150 -(4*22/7)*100*100)/(4*22/7-100*100)=125%
• 12 years agoHelpfull: Yes(5) No(0)
• 2x+ x^2/100
• 12 years agoHelpfull: Yes(0) No(2)
• b 125%
  area of sphere is 4pir^2 .
• 10 years agoHelpfull: Yes(0) No(0)