The average age of a woman and her daughter is 16 years. The ratio of their ages in 7 : 1 respectively. What is the woman’s age?
a. 4 years
b. 28 years
c. 32 years
d. 6 years
e. None of these

• The average age of a woman and her daughter is 16 years.
  sum of ages = 16*2=32 years.
  
  The ratio of their ages in 7 : 1 say 7x and x.
  then 8x = 32
  x=4
  Then age of woman = 7x = 28 years .. option b)
• 12 years agoHelpfull: Yes(9) No(0)
• Shortcut:
  Average=16. so Total=32.
  The total ratio of their age=7+1=8
  The womens age= (32/8)*7=28.
  Ans:b
• 12 years agoHelpfull: Yes(1) No(0)
• HERE THE AGES ARE IN RATIO 7:1 SAY 7X AND X
  THEREFORE:7X+X/2=16
  8X=32
  X=4
  THEREFORE AGE OF MOTHER =28
  
• 12 years agoHelpfull: Yes(0) No(0)
• avg age is W+D/2=16
  W+D=32
  given ratio 7:1
  7/8*32=28
• 7 years agoHelpfull: Yes(0) No(0)
• option:b is correct
  
• 7 years agoHelpfull: Yes(0) No(0)
• Let women be w and daughter be d
  Then (w+d)/2 =16 and w:d= 7:1 then w= 28 and d= 4
• 6 years agoHelpfull: Yes(0) No(0)
• since avg is given, so the total age= 16*2=32
  and ratio is given
  7:1 so, 7/8*32=28 yrs=womens age
  and, 1/8*32=4yrs=daughter age
• 5 years agoHelpfull: Yes(0) No(0)
• W+D=32
  W:D=7:1
  W=7D
  7D+D=32
  8D=32
  D=4
  W=28
• 5 years agoHelpfull: Yes(0) No(0)
• It is given that average age of a women and her daughter is 16 years.
  so, let women be 'W'
  let daughter be 'D'
  W+D/2=16 (equation 1)
  
  It is given that their ratio is 7:1
  so, W/D=7/1
  W=7D(equation 2)
  
  solve equation 1 by using the value of W in equation 2
  that is
  
  (W+D)/2=16
  7D+D=16*2 (PUTTING THE VALUE OF W FROM EQUATION 2)
  8D=32
  D=4
  
  NOW,
  PUT THE VALUE OF D IN EQUATION 2
  W=7D
  W=7*4
  W=28 YEARS.
• 1 year agoHelpfull: Yes(0) No(0)