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A bag has 10 bulbs of which 3 are defective.If three bulbs are drawn in succession without replacement,the prabability of all the three being defective is
a)(3/10)^3 b)1/120 c)1/80 d)7/120
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- A bag has 10 bulbs of which 3 are defective.If three bulbs are drawn in succession without replacement,the prabability of all the three being defective = (3/10)*(2/9)*(1/8) = 1/120 ... option b)
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