A person travels from P to Q at a speed of 40 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips?
A. 36 kmph B. 45 kmph
C. 48 kmph D. 50 kmph

• C. 48 kmph
  
  A person travels from P to Q at a speed of 40 km/hr and returns by increasing his speed by 50% i.e 60 km/hr.
  his average speed for both the trips = 2*40*60/100 = 48 kmph
• 13 years agoHelpfull: Yes(18) No(2)
• Ans:D.50kmph
  A person travels P-Q speed=40km/hr
  Return increasing 50%. So 60km/hr
  His avg speed for both the trips(go and return)=(40+60)/2=50
• 13 years agoHelpfull: Yes(4) No(9)
• Average speed of equal distance = (2xy)/(x+Y)
• 9 years agoHelpfull: Yes(4) No(0)
• D. 50kmph
  A travels P to Q is 40 kmph
  
  (40*50)/100=20
  Returns by Q to P is 60 kmph
  
  So average is 64+40/2=50kmph
• 10 years agoHelpfull: Yes(2) No(7)
• 48
  2*40*60/(40+60)=48
• 9 years agoHelpfull: Yes(1) No(0)
• p2 q=40
  q2p=40+40*50/100=60
  so,avg speed.=2*40*60/40+60
  avg.48
  so,avg.=48
• 9 years agoHelpfull: Yes(1) No(0)
• orignal speed =40 km/hr from p to q let it be x
  returning speed = 150% of 40 = 60 let it be y
  average speed = 2xy/x+y
  so 2*40*60/60+40=48 ans
  
• 9 years agoHelpfull: Yes(0) No(0)
• c
  
  avg speed=total distance/total time
• 9 years agoHelpfull: Yes(0) No(0)
• initial 40 km/h, on return 60km/h. average = (40+60)/2=50
• 9 years agoHelpfull: Yes(0) No(1)
• ans D. 50
  because when he return speed will increase 50% so we take 40*50100=20
  and 40+20= 60
  this is return speed=60
  p to Q speed= 40
  then we will find average speed = 40+602
  ans 50
• 9 years agoHelpfull: Yes(0) No(0)
• P to Q speed is 40kmph and return speed is 50% more i.e, 60kmph. then the average speed is 48kmph.
• 9 years agoHelpfull: Yes(0) No(0)
• option D.
  40+60/2=50
• 9 years agoHelpfull: Yes(0) No(2)
• Initial speed =40 kmph
  New speed=40+(0.5*40)= 60kmph
  Average=50kmph
• 9 years agoHelpfull: Yes(0) No(2)
• a person travels P to Q at 40 kmph
  But when that returning the same distance with increasing his speed by 50%.
  that means, the returning increasing speed is= (40/100)*50=20 kmph
  the returning speed is= 40+20= 60kmph
  
  therefore, the average speed of the both the trips is=(2*40*60)/(40+60)=4800/100=48kmph
• 4 years agoHelpfull: Yes(0) No(0)