The distance between two cities A and B is 330 Km. A train starts from A at 8 a.m. and travel towards B at 60 km/hr. Another train starts from B at 9 a.m and travels towards A at 75 Km/hr. At what time do they meet?
A. 10 a.m B. 10.30 a.m
C. 11 a.m D. 11.30 a.m

• C. 11 a.m
  
  Suppose they meet after x hrs from 9 AM.
  
  then
  60*(x+1) + 75*x = 330
  135 x = 330 -60= 270
  x= 270/135 = 2 hrs
  
  so the trains will met at 11 AM.
• 13 years agoHelpfull: Yes(15) No(1)
• ANS :C
  total distance is 330 ,
  train B starts at 9 A.M so in one hour Train A covers 60km remining distance is
  330-60=270.
  time to meet both the trains=1hr+(remainingdistance)/(v1+v2)
  i.e 270/132=1+2=3hr
  so they will meet at 8+3=11AM
• 13 years agoHelpfull: Yes(5) No(3)
• A train goes in 1 hour = 60 km.
  So, remaining distance = 330-60 = 270 km
  Now both the train are opposite direction, so relative speed = (75+60) = 135 km/hr
  Now, Time = Distance/speed = 270/135 = 2 hour.
  So, 9 am + 2 hour = 11 am they are meet.
• 8 years agoHelpfull: Yes(4) No(0)