A and B can do a piece of work in 12 days, B and C can do it in 15 days and C and A can do the same work in 20 days. How long would each take to complete the job?
a>1/30, 1/20, 1/60
b>1/20, 1/30, 1/30
c>1/20, 1/20, 1/20
d>1/60, 1/0, 1/30

• (A+B)'s one day work is 1/12
  (B+C)'s one day work is 1/15
  (C+A)'s one day work is 1/20
  Thus,2(A+B+C)'s one day work is 1/12+1/15+1/20=1/5
  so,(A+B+C) can complete the work in 10 days.
  (A+B+C)'s one day work=1/10
  A 's one day work=1/10-1/15=1/30
  B's one day work=1/10-1/20=1/20
  C's one day work=1/10-1/12=1/60
  The answer option shall be a
  However, the answer is given in one day's work.
  Otherwise the answer would be 30,20 and 60 days.
• 12 years agoHelpfull: Yes(10) No(2)
• OPTION A>1/30,1/20,1/60
  A+B=1/12
  B+C=1/15
  C+A=1/20
  (A+B)+(B+C)+(C+A)=2(A+B+C)=1/12+1/15+1/20
  (A+B+C)'s one day work = 12/120=1/10
  A'S one day work=(A+B+C)-(B+C)=1/10-1/15=1/30
  B'S one day work=(A+B+C)-(C+A)=1/10-1/20=1/20
  C'S one day work=(A+B+C)-(A+B)=1/10-1/12=1/60
• 11 years agoHelpfull: Yes(4) No(1)