If 34 men completed 2/5th of a work in 8 days working 9 hours a day. How many more man should be engaged to finish the rest of the work in 6 days working 9 hours a day?

• Apply the MHD rule: (M1*H1*D1)/w1=(M2*H2*D2)/w2
  Here, w1=2/5=0.4 and w2 being the remaining work 0.6
  (34*9*8)/0.4=(M2*9*6)/0.6
  Solving, we get M2=68
  Thus, 34 more men shall be engaged(68-34)
• 12 years agoHelpfull: Yes(13) No(6)