A certain number of men can do a work in 20 days. If there were 4 more men, the work can be done in 5 days less.How many men were there initially?

• 12 men
  
  If there are x men initially then
  no of man days reqd =
  x* 20 = (x+4)*15
  
  then
  20x = 15x +60
  x= 60/5 =12 men
• 13 years agoHelpfull: Yes(14) No(0)
• let, there are x man
  so, 1 man's 1 day's work=1/(20*x)
  after adding 4 man
  1 man's one day's work=1/15(x+4)
  now,
  1/(20*x)=1/15(x+4)
  3x+12=4x
  x=12
• 13 years agoHelpfull: Yes(3) No(0)
• x*20=(x+4)*15
  20x=15x+60
  5x=60
  x=12
  Ans:men=12
  
• 13 years agoHelpfull: Yes(2) No(0)
• 12 men.
  let,x be the initial no. of men.
  then x's 1 day work=1/20.
  a/c to the problem,
  (x+4)'s 1 day work=1/15.
  so,
  x:(x+4)=(1/20):(1/15)
  therefore,5*x=60
  x=12 men ans.
• 12 years agoHelpfull: Yes(1) No(0)
• let initial men will be x
  then work done by x men in 20 days will b = x*20
  and same work done by x+4 men in 15 days will b = x+4*15
  both the wrk are same so..
  x*20 = (x+4)*15
  ans will b 12 men..
• 12 years agoHelpfull: Yes(1) No(0)