Wipro Company Numerical Ability Time and Work

A and B together can do a piece of work in 14 2/5 days; B and C together can do the same work in 12 days. After A worked for 8 days, B for 12 days C takes up and finished it alone in 6 days. In how many days will each of them do the work, working alone?

Read Solution (Total 1)

A's 8day work+B's 12 days work+C's 6days work=1
(A+B)'s 8 day work+(B+C)'s 4day work+C's 2day work=1
=>8/(14 2/5)+4/12+C's 2day work=1
=>C's 2 day work=1-4/12-40/72=1/9
=>C's 1day work=1/18
so C can finish in18days.
As B+C 's 4 day work is=4/12.sso B+C 's 1day work=1/12
so B can finish it in=1/(1/12-1/18)=36days.
so A can finish it in 24days.
13 years agoHelpfull: Yes(15) No(21)

Wipro Other Question

To do a certain work C alone takes twice as long as A and B together. A would take 3 times as long as B and C together. All three together complete the work in 5 days. How long would each take separately? A can do a work in 12 days.When he had worked for 3 days B joined him. If they complete the work in 3 more days. In how many days can B alone can finish the work?