CSC
Company
Numerical Ability
Time Distance and Speed
A runs 5/3 times as fast as B. If A gives B a start of 80 m, how far must the winning post be so that A and B might reach it at the same time?
A. 200 m B. 300 m
C. 270 m D. 160 m
Read Solution (Total 2)
-
Ratio of the speeds of A and B = 5 : 1 = 5 : 3.
3
Thus, in race of 5 m, A gains 2 m over B.
2 m are gained by A in a race of 5 m.
80 m will be gained by A in race of 5 x 80 m = 200 m.
2
Winning post is 200 m away from the starting point.- 12 years agoHelpfull: Yes(1) No(1)
- Ratio of the speeds of A and B = 5 : 1 = 5 : 3.
3
Thus, in race of 5 m, A gains 2 m over B.
2 m are gained by A in a race of 5 m.
80 m will be gained by A in race of 5 x 80 m = 200 m.
2
Winning post is 200 m away from the starting point. - 11 years agoHelpfull: Yes(0) No(0)
CSC Other Question