exam Maths Puzzle Numerical Ability

.1X+.99Y+.13Z=.5[X+Y+Z]
.99X+.05Y+.02Z=.24[X+Y+Z]
X:Y:Z=1:.94:2.59[THIS IS THE ANSWER TO THE ABOVE TWO EQUATION.I WOULD LIKE A STEP BY STEP BREAKDOWN AS TO HOW THIS ANSWER WAS O

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solve having problems with this one

x^2-9 over 4x-12 show work

this is what I came up with

(x-3)(x+3) over 4(x+3)

answer: x-3 over 4 Any help would be really appreciated please. Ta

This is the last of my problems for now, I am really stuck. I do not know how to get the x and the y onto the same side with the = at the end. Ta

I have solve for X and Y

y=9-3x
x=8-2y