When three integers are added two at a time, three distinct sums are formed: 32, 48, and 46. What is the sum of all three of the original numbers?

• let , the numbers be x,y,z:
  so, x+y=32, y+z=48, x+z=46.
  2(x+y+z)=32+48+46=126.
  so, x+y+z=126/2=63.
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