The difference of two numbers is 14.their lcm and hcf are 441 and 7.find the numbers.
a, 21,35
b, 35,49
c, 49,63
d, 63,77

• c) 49,63
  
  
  Since their HCFs are 7, numbers are divisible by 7 and are of the form 7x and 7y
  
  Difference = 14
  => 7x - 7y = 14
  => x - y = 2
  
  product of numbers = product of their hcf and lcm
  => 7x * 7y = 441 * 7
  => x * y = 63
  
  Now, we have
  x * y = 63 , x - y = 2
  =>x = 9 , y = 7
  
  The numbers are 7x and 7y
  => 63 and 49
  => option c
• 9 years agoHelpfull: Yes(46) No(0)
• since n1*n2=hcf*lcm
  apply this formula nd check it from solution
  hcf*lcm =441*7=------( first digit is 7)so check only 49,63 after multiplying gives frist digit 7.
• 9 years agoHelpfull: Yes(13) No(0)
• try to solve through option see 441*7 its first digit is 7 and in option by checking all only 49*63 has 7 at its first digit so ans is 49,63.
• 9 years agoHelpfull: Yes(8) No(0)
• Let 1st no=x,2nd no=y,
  A/c to qustn,x-y=14
  x=14+y
  we know,
  HCF*LCM=n1*n2
  7*441=x*y
  3087=(14+y)*y
  3087=14y+y^2
  y^2+14y-3087=0
  y^2+63y-49y-3087=0
  y(y+63) -49(y+63)=0
  (y-49) (y+63)=0
  so,y=49,then x=y+14=49+49=63
  Hence,nos are 49 and 63.
• 8 years agoHelpfull: Yes(3) No(0)
• 49,63 USING
  7A*7B=441
  7A-7B=2
• 9 years agoHelpfull: Yes(2) No(0)
• product of two nos=LCM*HCF
  therefore 441*7=49*63 through option
• 9 years agoHelpfull: Yes(1) No(0)
• easy trick...check by options...
  a) LCM(21,35)= 105 & HCF(21,35)=7
  B) LCM(35,49)=245 & HCF(35,49)=7
  C)LCM(49,63)=441 & HCF(49,63)=7
  D)LCM(63,77)=693 & HCF(63,77)=7
  So the answer is c.
• 9 years agoHelpfull: Yes(1) No(1)
• answer is part c.
  lcm*hcf= no.
  441*7=7*7*7*9=49,63
  63-49=14
  
• 8 years agoHelpfull: Yes(1) No(0)
• step 1:- product of two numbers = LCM of numbers * HCF of numbers
  = 441 * 7
  = 3087
  
  step 2:- take a look which pairs from option gives 3087 on multiplying
  
  option (c) = 49 * 63 = 3087 (also holds the property that HCF of numbers divides it fully i.e 7 divides 49 and 63 completely).
  
  step 3:- option (c) is the correct choice.
  
• 7 years agoHelpfull: Yes(1) No(0)
• The LCM is to be checked since the HCF and the difference is satisfied in all the other options.
  Answer. c. 49,63
• 9 years agoHelpfull: Yes(0) No(0)
• 441/7= 63
  441*7/63=441/9= 47
• 9 years agoHelpfull: Yes(0) No(0)
• Ans is c
  x^2-(14)x-3087=0
  i will form bcoz lcm*hcf =product of numbers
• 9 years agoHelpfull: Yes(0) No(0)
• by checking options we get lcm 441 only for 49 nd 63
• 9 years agoHelpfull: Yes(0) No(0)
• are this level questions comes in elitmus?
  
• 9 years agoHelpfull: Yes(0) No(0)
• by the help of option u can answer.......answer is C
  
• 9 years agoHelpfull: Yes(0) No(0)
• option c is the ans.
  
• 9 years agoHelpfull: Yes(0) No(0)
• (a+b)^2=(a-b)^2+4ab;
  (a+b)^2=14^2+4*441*7; (since a*b=lcm*hcf,and a-b=14 given)
  a+b=112;..................(i)
  and a-b=14;............................(ii)
  so add (i) and (ii) and get
  a=63;
  and b=49; (by putting the value of a in equation (i) get b);
  answer - c;
• 9 years agoHelpfull: Yes(0) No(0)
• no = hcf*LCM
  = 441*7
  = 3087
  NOW MULTIPLICATIN OF TWON NO EQUALLS TO THAT NO
  SO 49*63=3087
  ANS-C
• 9 years agoHelpfull: Yes(0) No(0)
• let the numbers are x and y
  according to question x-y=14
  then, x=14+y
  
  so we know x*y=HCF*LCM
  
  (14+y)*y=441*7
  y^2+14y-3067=0
  y= -63, 49
  y=49
  x=14+y=63
• 9 years agoHelpfull: Yes(0) No(0)
• Let one number be X. Other number will be 14+X.
  Since, HCF and LCM are given
  X*(X+14)=HCF*LCM
  X^2+14X-144*7=0
  Solving the quadratic equation,
  X=49
  Other number 49+14=63
  49,63
  
• 8 years agoHelpfull: Yes(0) No(0)
• c because a*b=lcm*hcf
• 8 years agoHelpfull: Yes(0) No(0)
• 
  (c) 49,63
• 8 years agoHelpfull: Yes(0) No(0)
• c)49,63
  Let a no is x, then other is x-14.
  product of numbers= hcf*lcm.
  x*(x-14)=441*7
  
  from solving
  u'll find the no. r 49 and 63.
• 8 years agoHelpfull: Yes(0) No(0)
• Go through option and check only lcm of those, b'coz difference and hcf of all those options have same, only option- C has lcm as 441 . that's why option C is correct
• 8 years agoHelpfull: Yes(0) No(0)
• (c)=49,63 ans
  
• 8 years agoHelpfull: Yes(0) No(0)
• option c is right
• 7 years agoHelpfull: Yes(0) No(0)
• c . 49,63
• 6 years agoHelpfull: Yes(0) No(0)
• 49,63
  xy*hcf=lcm
  xy=63
  x-y=14
• 5 years agoHelpfull: Yes(0) No(0)
• c is the answer as we know the hcf of 49 and 63 is 7 and the 441 is the bigger number so try to find a big number whose lcm can give you a number 441 so answer is c
• 4 years agoHelpfull: Yes(0) No(0)