book Maths Puzzle Numerical Ability

The tens digit of a three digit number is half the units digit and thrice the hundreds digit. If the digits are reversed, the new number is 49 more than thrice the original number.

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I also need help with simplifying this problem:

(a^1/3 b^1/6)^2 (a^1/3 b^2/3).

I am not quite sure what to do with this. I usually dont have a problem simplifying but this is just confusing to me. Will some one help me understand it? what are these types of problems called, and how do you do them. Are their ny links you can refer me too. 5^(6-x) or like 5^(x/3) things of this nature and some more complex. thanks