A bus starts from city X. The number of women in the bus is half of the number of men. In city Y, 10 men leave the bus and five women enter. Now, number of men and women is equal. In the beginning, how many passengers entered the bus ?

A. 15 B. 30
C. 36 D. 45

• no of women be A
  no of men be B
  in city X -> A=B/2-----(1)
  in city Y -> A+5=B-10
  B-A=15
  from 1 B=2A sub in above equation
  2A-A=15
  A=15 means B=30
  in the beginning no of passengers entered the bus is A+B=30+15=45
• 13 years agoHelpfull: Yes(6) No(0)
• Let number of women = x. Then, number of men = 2x.
  So, in city Y, we have : (2x - 10) = (x + 5) or x - 15.
  
  Therefore Total number of passengers in the beginning = (x + 2x) = 3x = 45
• 10 years agoHelpfull: Yes(1) No(1)