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In a cricket match, five batsmen A, B, C, D and E scored an average of 36 runs. D Scored 5 more than E; E scored 8 fewer than A; B scored as many as D and E combined; and B and C scored 107 between them. How many runs did E score ?
A. 62 B. 45
C. 28 D. 20
Read Solution (Total 1)
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- Option D 20
a+b+c+d+e=36*5=180
b+c=107
a=x
e=x-8
d=x-3
now 3x-11+107=180
3x=84
x=28
e's score=28-8=20 - 12 years agoHelpfull: Yes(11) No(0)
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