CSC
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Numerical Ability
Algebra
At a dinner party every two guests used a bowl of rice between them, every three guests used a bowl of dal between them and every four used a bowl of meat between them. There were altogether 65 dishes. How many guests were present at the party ?
A. 60
B. 65
C. 90
D. None of these
Read Solution (Total 2)
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- A.60
no. of rice bowl=x
no. of dal bowl=y
no. of meat bowl=z
then, x+y+z=65(eq 1)
also, 2x=3y=4z
substituting value of y&z in terms of x in eq 1, x=30.
as 1 rice bowl is shared between 2 guests, therefore there are 60 guests... - 12 years agoHelpfull: Yes(10) No(1)
- A.60
Consider total x guests
(x/2) bowl of rice
(x/3) bowl of dal
(x/4) bowl of meat
(x/2)+(x/3)+(x/4)=65
6x+4x+3x=65*12
x=(65/13)*12
x=60 - 10 years agoHelpfull: Yes(8) No(0)
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