Wipro
Company
Numerical Ability
Log and Antilog
[1+(1/5)]^n=2?
What is the value of n?
Read Solution (Total 3)
-
- value of N = 4 (3.8)
1+1/5 = 6/5 = 1.2
1.2*1.2 = 1.44 *1.2 = 1.728 *1.2 = 2.0736
so if N is integer, N=4. if not, N = 3.8
(1.2)^3.8 = 1.999 - 13 years agoHelpfull: Yes(15) No(7)
- ans
log(6/5)^n=log2
n*log6/5=log2
n*0.079=3.8
n=3.8/.079=3.81
- 12 years agoHelpfull: Yes(2) No(2)
- hey there is some mistake in my previous solution..the value of log2 should be 0.30....i.e it is 0.30 in place of 3.8..
- 12 years agoHelpfull: Yes(2) No(2)
Wipro Other Question