Find the total number of combinations of 5 alphabets A,B,A,B,B taking some or all at time.

• 1 letter can be chosen in 2 ways. a or b
  2 letters can be chosen in 3 way. aa, ab, bb
  3 letters can be chosen in 3 ways. bbb, aab, bba
  4 letters can be chosen in 2 ways. aabb, bbba
  5 letters can be chosen in 1 way.
  So total ways are 11
• 9 years agoHelpfull: Yes(41) No(2)
• answer is 10
• 9 years agoHelpfull: Yes(4) No(8)
• ans.11 ways
  1 letter can be chosen in 2 ways. a or b
  2 letters can be chosen in 3 way. aa, ab, bb
  3 letters can be chosen in 3 ways. bbb, aab, bba
  4 letters can be chosen in 2 ways. aabb, bbba
  5 letters can be chosen in 1 way.
  So total ways are 11
• 9 years agoHelpfull: Yes(4) No(1)
• Ans. is 11
• 9 years agoHelpfull: Yes(3) No(2)
• answer is 11
• 9 years agoHelpfull: Yes(2) No(4)
• It should be 5!/(2!*3!) =10
  m i right ??
  
• 9 years agoHelpfull: Yes(1) No(5)
• As A occurs 2 times, we can choose A in 2+1 ways
  
  So, the number of ways of selection of no or more letters from the word:
  ABABB will be N=(2+1)(3+1)
  Clearly, this contains one combination of choosing no letter
  
  So, the number of ways of selection of one or more letters will be N−1
  the ans is==12-1=11
  11 ways or combinations
• 8 years agoHelpfull: Yes(0) No(0)