If a2 + b2 + c2 = 250 and ab + bc + ca = 3, then a + b + c is

• by formula ,
  
  (a + b + c)^2= a^2 + b^2 + c^2 + 2(ab + bc + ca),
  
  since, a^2 + b^2 + c^2 = 250 and ab + bc + ca = 3,
  
  (a + b + c)^2 = 250 + 2(3)
  = 256
  = 16^2
  
  therefore: a + b + c = 16 ,.
  
• 13 years agoHelpfull: Yes(15) No(6)
• 16
  coz
  (a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)
  =250+6
  =256
  and a+b+c=16
• 13 years agoHelpfull: Yes(4) No(0)
• (a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)
  (a+b+c)^2=250+2*(3)
  (a+b+c)^2=256
  a+b+c=16
• 13 years agoHelpfull: Yes(4) No(1)
• (a+b+c)2=a2+b2+c2+2(ab+bc+ca)
  applying we get:
  (a+b+c)2=250+6
  a+b+c=16
• 13 years agoHelpfull: Yes(3) No(1)
• (a+b+c)2=a2+b2+c2+2(ab+bc+ca)
  =250+2(3)
  =256
  =>a+b+c=16
• 13 years agoHelpfull: Yes(2) No(0)
• (a+b+c)2=a2+b2+c2+2(a+b+c)=250+2(3)=250+6=256
  a+b+c=16
  
• 13 years agoHelpfull: Yes(2) No(1)
• 16....(a+b+c)2
• 10 years agoHelpfull: Yes(1) No(0)
• from the formula (a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)
  250+6=256
  a+b+c=16
• 9 years agoHelpfull: Yes(0) No(0)