If an integer "k" is divisible by 2,5 and 13.what is the next largest number that is divisible by all the three given numbers?
a, k+13
b, k+130
c, 2k
d, 2k+13
e, 2k+65

• LCM of 2,5,13 is 130
  so k=130
  2k also the correct answer,but we need to find next largest number
  therefore ans is k+130
• 9 years agoHelpfull: Yes(20) No(2)
• LCM of 2, 5 , 13 = 130
  if k = 260
  k+130 = 390
  2k = 520
  
  c) 2k
  
• 9 years agoHelpfull: Yes(7) No(13)
• we take lcm of 2,5 and 13. then we get 130 which is divisible by all the digits , so we simply add 130 to the integer "k"
  ANS::: k+130
• 9 years agoHelpfull: Yes(6) No(1)
• the value which is divisible by 2 , 5 and 13 so ans is k+130
• 9 years agoHelpfull: Yes(4) No(0)
• k+hcf(2,5,13)
  k+130
• 9 years agoHelpfull: Yes(2) No(1)
• as L.C.M of 2,5,13 is 130
  here k can be taken any value multiple of 130
  So the next largest number divisible can be 2k or k+130
• 9 years agoHelpfull: Yes(1) No(3)
• 130/2 = 65
  130/5=26
  130/13=10
  so next value is k+130 = 260 which is divisible by all given numbers
• 9 years agoHelpfull: Yes(1) No(0)
• let us consider k=260.
  it is divisible by 2,5,13
  next k+130. k is 260 and k+130 is 390.
  390 is divisible by above 3 digits.
  soo the answer is k+130.
• 8 years agoHelpfull: Yes(0) No(0)
• b
  LCM of 2 5 and 13=130
  if K is current number divisible by 2,3 and 13 then next higher number is k+130(multiple of 130).
  Also k too is a multiple of 130.
• 6 years agoHelpfull: Yes(0) No(0)