A man if travels at 5/6 th of his actual speed takes 10 min more to travel a distance. Find his usual time.

• Ans is 50 min
  Explanation :
  Let s be the actual speed and t be the actual time of the man.
  Now the speed is (5/6)s and time is (t+10) min. But the distance remains the same.
  So distance 1 = distance 2 => s X t = (5/6)s X (t+10) => t = 50 min.
• 12 years agoHelpfull: Yes(1) No(0)
• new speed=5/6 of actual speed
  new time 6/5 of actual time
  6/5 of actual time-actual time=10min
  6/5-1=10 min
  1/5=10 min
  1=10*5=50 mins
• 10 years agoHelpfull: Yes(0) No(0)