A person bought two watches for Rs.480. He sold one at a loss of 15% and the other at a gain of 19% and he found that each watch was sold at the same price. Find the cost price of the two watches.

• CP1 = 200
  CP2 = 280
• 10 years agoHelpfull: Yes(1) No(0)
• Let c.p. of 1st watch=Rs. x. Then c.p. of 2nd watch=Rs.(480-x)
  A/q,
  85% of x=119% of (480-x)
  Solving we get,x=Rs.280
  So, c.p of 1st watch= Rs. 280 and c.p of 2nd watch=Rs.(480-280)=Rs. 200.
• 6 years agoHelpfull: Yes(1) No(0)
• (119/100)CP1=CP2(85/100) (since both sp are equal)
  cp1+cp2=480
  cp1=cp1
  cp2=cp1(119/85)
  by solving we get
  cp1=200;
  cp2=280;
  here we use the formulae
  cp=(100/(100+g)100)sp
  for loss replace + with - and g with l
• 10 years agoHelpfull: Yes(0) No(3)