exam
Maths Puzzle
Numerical Ability
A certain sum of money is invested at 10%. Twice that amount is invested at 8%. The total amount of interest from both investments is $91. How much is invested at 8%.
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xy + 3z + y =
please solve the problem for me.
nC0.nCn + nC1.nCn-1 + nC2.nCn-2 + ...........+nCn.nC0=(2n!)/(n!)^2