Walking 6/7th of his usual speed, a man is 12 minutes too late. The usual time taken by him to cover that distance is:
1. 2 hour
2. 1 hr 12 min.
3. 1 hr 15 min.
4. 45 min

• option 2 1 hour 12 minutes
  
  As the distance is same
  s*t=6/7s*(t+12)
  t=72 min
  1 hour 12 min
• 12 years agoHelpfull: Yes(22) No(8)
• 6/7 of s
  so 7/6 of time we get.
  then new time=7/6 t
  usual time =t
  then 7/6-t=12/60
  (1/6)t=1/5
  t=6/5hours
  i.e 6/5*60=72 mins=1 hour 12 mins
  
• 9 years agoHelpfull: Yes(10) No(0)
• t is inversely prpotional to speed
  t=7/6 1/6 bigger so
  1/6*x=12
  x=1hr 12 min
• 10 years agoHelpfull: Yes(4) No(0)
• Justification:
  New speed = (6/7) of usual speed.
  New time = (7/6) of usual time.
  Therefore (7/6 of usual time)- (usual time) = (1/5) hr.
  => (1/6 of usual time)= (1/5) hr
  => usual time = (6/5) hr
  = 1 hr 12 min.
• 9 years agoHelpfull: Yes(2) No(1)
• Distance traveled is same in both the case . Let distance be D.
  Now, let usual speed is x . so , 6/7 of usual speed is (6/7)x.
  
  Now, it is given that when men walks 6/7th of his usual speed, he is 12 minutes too late . Which means difference between usual time taken to the time taken when he is walking (6/7) of his usual speed is 12.
  
  We know that -
  Distance/Speed=Time
  Therefore,
  (D/(6x/7))-(D/x)=12
  Solving this we get-
  D/x=72min. which is nothing but usual speed.
  Now converting it into hour we get our answer which is 1hr 12min.
• 7 years agoHelpfull: Yes(1) No(0)
• 1hr 12 min
• 7 years agoHelpfull: Yes(1) No(0)