The sum of the ages of a married couple is 60. If three times the age of the husband is nine less than four times the age of the wife, how old are they now?

• Let the age of wife be x years, and age of husband be (60-x) years.
  now,
  3(60-x) = 4x-9
  180- 3x = 4x-9
  7x = 189
  x= 27
  
  hence age of wife is 27 years and husband age is 33 years.
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• X+y=60
  3x=4y-9
  Solving above we get x=36,y=24
• 8 years agoHelpfull: Yes(0) No(0)