Albert buys 4 horses and9 cows for Rs.13,400. If he sells the horses at 10% profit and the cows at 20% profit, then he earns a total profit of Rs.1880. The cost of a horse is:
1. Rs. 2200
2. Rs. 2000
3. Rs. 2700
4. Rs. 3200

• Let x denote 4 horses and y denote 9 cows
  
  then,
  
  x+y=13400
  
  and (x+0.1x)+(y+0.2y)=13400+1880=15280
  or, 1.1x+1.2y=15280
  and x+y=13400
  
  Solving we get,x=8000
  
  Therefore cost of one horse=8000/4=Rs. 2000
• 10 years agoHelpfull: Yes(7) No(0)
• 2. 2000
  NOT USEFUL BUT,
  SOLVE BY OPTIONS.
• 10 years agoHelpfull: Yes(1) No(1)
• let horse cp = a , cow cp = y ;
  4a+9b=13400; (let say equation 1)
  4a*10/100+9b*20/100=1880
  after solve we get
  2a+9b=9400 ( let say this is equation 2)
  
  after solving both equation we get
  x=2000 (Answer)
• 7 years agoHelpfull: Yes(0) No(0)