A man purchases two clocksA andB at a total cost of Rs. 650. He sellsA with 20% profit and B at a loss of 25% and gets the same selling price for both the clocks. What are the purchasing prices ofA and B respectively?
1. Rs. 550, Rs. 660
2. Rs. 250, Rs. 400
3. Rs. 378, Rs. 375
4. Rs. 300, Rs. 350

• 2) Rs. 250 , Rs. 400
  Let CP of A be x so CP of B will be 650-x
  Given that on selling A with 20% profit and selling B with 20% loss Sp would be equal.
  
  
  So (120/100)*x = (75/100)*(650-x)
  
  Solving above x==>250 and y=650-250 ==>400
  
• 10 years agoHelpfull: Yes(5) No(0)
• Rs. 250, Rs. 400
• 11 years agoHelpfull: Yes(2) No(2)
• 20% profit of 250 is 300 and 25% loss of 400 is 300 in this way answer is 250,400
• 11 years agoHelpfull: Yes(1) No(1)
• given he got profit of 20% on A and loss of 25% on B for same selling price ....so
  (100-loss%)*cpA100=(100+gain%)*cpB100.
  75*cpA=120*cpB
  =>cpAcpB=5/8;--------------(1)
  from the first sentence
  cpA+cpB=650----------------(2)
  by solving both equations (1) and(2) we get cpA=250 and cpB=400.
• 10 years agoHelpfull: Yes(0) No(0)