If an airplane starts at point R and travels 14 miles directly north to S, then 48 miles directly east to T, what is the straight-line distance (in miles) from T to R?
option
(a) 25
(b) 34
(c) 50
(d) 2500

• N
  W E
  S these are the directions
  apply the conditions in this directions
  where R is a point in north and S is in south T is in east
  form a triangle then find the distance by
  hypotenuse=sqrt(oppositeside^2+adjecentside^2)
  answer is 50
• 14 years agoHelpfull: Yes(5) No(0)
• sqrt(14^2+48^2)=50
• 14 years agoHelpfull: Yes(1) No(0)
• answer is 50
  the airplane travel makes a triangle with opposite side length as 14 miles and adjacent side length as 48 miles. now find the hypotenuse using pythagoras theorem.
  hypotenuse = sqrt ( opp. side ^ 2 + adj.side ^ 2)
  sqrt(14^2+48^2) = 50
• 14 years agoHelpfull: Yes(0) No(0)
• R
  .
  .
  .
  s.........T
  RS=14
  ST=48
  TR=SQRT{(RS)^2+(ST)^2}
  TR=SQRT{14^2+48^2}
  TR=50 MILES
• 12 years agoHelpfull: Yes(0) No(0)
• ans=50 miles
  as we know,
  __N
  W___E
  __S
  applying condition,
  R(N)
  |
  |
  S________T (R-S=14 miles,S-T=48 miles)
  joining T-R, it makes right angled triangle
  TR= sq.rt(14^2+48^2)
  =sq.rt(196+2304)
  =sq.rt(2500)
  =50
• 11 years agoHelpfull: Yes(0) No(0)