In a software company 2/6 of people know C++,1/2 of them know java,1/5 of them know
neither,find the total possibility to know C++?

• 1/5 doesnot know anything means 1- 1/5 =4/5 knows programming
  By AUB = A + B - (A Intersection B)
  4/5 = 2/6 + 1/2 - x
  x = 1/30
  So 1/30 Knows Both java n C ++
  
  now the possibility of knowing only C++ is
  2/6-1/30=3/10
• 10 years agoHelpfull: Yes(39) No(5)
• 1/5 doesnot know anything means 1- 1/5 =4/5 knows programming
  By AUB = A + B - (A Intersection B)
  4/5 = 2/6 + 1/2 - x
  x = 1/30
  So 1/30 Knows Both java n C ++
  
  now the possibility of knowing C++ is
  
  (2/6)/(2/6+1/2+1/30)
  
  =5/13.
• 10 years agoHelpfull: Yes(13) No(5)
• 1/5 doesnot know anything means 1- 1/5 =4/5 knows programming
  By AUB = A + B - (A Intersection B)
  4/5 = 2/6 + 1/2 - x
  x = 1/30
  So 1/30 Knows Both java n C ++
• 10 years agoHelpfull: Yes(3) No(12)
• AUB = A+ B -(A Intersectn B)
  
  = 2/6 + 1/2 - 1/5
  = 19/30
  Total possibility to know c++ = 2/6 % 19/30
  =10/19
  
• 10 years agoHelpfull: Yes(0) No(8)
• may be the ans is 4/5.........
  n(A)=2//6........ who know c++
  n(B)=1/2.......who know java
  n(A intersection B)=4/5(1-1/5).....is nothing but negation of n(A intersection B)
  who know only c++ n(A)=n(A intersection B)-n(A)
• 9 years agoHelpfull: Yes(0) No(0)
• 3/10..............
• 6 years agoHelpfull: Yes(0) No(0)
• C++ Known people = 2/6,
  Java Known people =1/2,
  Neither C++ Nor Java = 1/5,
  So,both known = 4/5,
  Only C++ = 4/5(Both Known) - 1/2(java Known people)
  = (8-5)/10
  = 3/10.
• 6 years agoHelpfull: Yes(0) No(0)