A bus started from bustand at 8.00am, and after 30 minutes staying at destination, it returned back to the busstand. The destination is 27 miles from the busstand. The speed of the bus is 18mph. In return journey bus travels with 50% fast speed. At what time it returns to the busstand?

• 
  A---------->B
  A->B
  time= 27/18=3/2hour= 90 min
  A reaches B at 9.30
  and waits in B for 30min
  b returns travelat 10 am
  speed=(150/100)18=27mph
  return time= 27/27=1hour
  B reaches A at 11am
  
  Answer: 11am
• 11 years agoHelpfull: Yes(38) No(0)
• bus reaches at10:45
• 11 years agoHelpfull: Yes(2) No(13)
• bus stand to destination will be covered in 1.5 hour so it will reach at destination 9:30 am after that 30 min rest . Then at 10:00 am it will start journey again.As in question specified returning speed will be 50% fast so new speed will be 18 of 150% that is 27mph so it will cover the distance from destination to bus stand in 1 hour.
  At 11:00 it will be in the bus stand.
• 10 years agoHelpfull: Yes(1) No(0)
• Bus Reaches at 1:00 P.M
• 11 years agoHelpfull: Yes(0) No(13)