Elitmus
Exam
Numerical Ability
Permutation and Combination
About 4 out of 5 students are left handed.If there are totally 40 students in an class.how many would be left handed?
a, 40
b, 30
c, 32
d, 42
Read Solution (Total 15)
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- 4 out of 5 => 80% students are left handed
so, total= 80% of 40 =40*80/100= 32 - 10 years agoHelpfull: Yes(31) No(1)
- I am pretty sure this is not a elitmus level question.
- 9 years agoHelpfull: Yes(17) No(0)
- 4 out of 5 Students are left handed
total students = 40
5 * 8 = 40
left handed 4*8=32 - 10 years agoHelpfull: Yes(3) No(0)
- 4 out of 5 means every 10 student 2 are not left handed... so in 40 student 8 are not .... 40-8=32 student are left handed
- 10 years agoHelpfull: Yes(3) No(0)
- Probability of left handed = 4/5
total student = 40
total left handed = 40 *(4/5)
= 32 - 10 years agoHelpfull: Yes(3) No(0)
- 40/5=8
4*8=32 ans - 10 years agoHelpfull: Yes(2) No(0)
- 4 out of 5 students are left handed
now total students is 40.means if we divide by 5 then we get 8 [5+ 5+ 5+ 5+ 5+ 5 +5 +5=40]
now if 4 out of 5 students are left handed then [4+4+4+4+4+4+4+4=32] are total left handy students out of 40. - 10 years agoHelpfull: Yes(2) No(2)
- ans is 4/5*40=32
- 10 years agoHelpfull: Yes(1) No(0)
- 32
80% are left handed
so 80% of 40 is= 32 - 9 years agoHelpfull: Yes(1) No(0)
- 32 since 5*8 = 40 therefore required ans is 4*8=32
- 10 years agoHelpfull: Yes(0) No(0)
- 32 left handed
- 9 years agoHelpfull: Yes(0) No(0)
- for every 10 students we get 8 left handed hence for 40 students we get 8*4=32 left handers.
- 9 years agoHelpfull: Yes(0) No(0)
- 4 out 5 are left handed so 4/5*40=32 would be left handed
- 9 years agoHelpfull: Yes(0) No(1)
- x+2+y+2+z+2=9
x+y+z=3
3+3-1c3-1=5c2
- 8 years agoHelpfull: Yes(0) No(1)
- C- 32
In 40 ,5 is divisible 8 times...for every 5 there are 4...so,8*4=32 - 5 years agoHelpfull: Yes(0) No(0)
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