Syntel
Company
Numerical Ability
Age Problem
kevin got married 8 years ago. his presen age is 6/5 times his age at the time of his marriage. kevin's sister was 10 years younger to him at the time of his marraige . The age of kevin's sister is
[A] 38
[C] 29
[B] 42
[D] 44
Read Solution (Total 6)
-
- given that kevin got married 8 years before say x years at the time of marriage
means now the age is x+8
and also given that now the is 6/5 times of his marriage
i.e x+8=(6/5)x
5x+40=6x
x=40 this is at the time of marriage
but at present the age is 40+8=48
his sister is 10 years younger then his sister age is 48-10=38
- 11 years agoHelpfull: Yes(28) No(1)
- kevin,s sister age is 38 years.
- 10 years agoHelpfull: Yes(2) No(1)
- let the kelvin present agr be x
8 year ago=x-8
according to question
x=6/58(x-8)
5x=6x-48
x=48
kelvin sister's age duing marriage
(48-8)-10
=30
present age of his sister30+8=38 - 10 years agoHelpfull: Yes(1) No(0)
- let kevins age be 'x' at the time of his marriage
kevin got married 8 yrs ago his presen age is 6/5 times his age at the time of his marriage i.e.,x+8=(6/5)x ==>x=40
kevins sister is 10 yrs younger than him so sister=x-10==>sister age at that time= 30
so present age is 38
- 10 years agoHelpfull: Yes(0) No(0)
- a =38 ans
- 10 years agoHelpfull: Yes(0) No(0)
- K=6*(K-8)/5
k=48
k=s+10
s=38 - 7 years agoHelpfull: Yes(0) No(0)
Syntel Other Question