kevin got married 8 years ago. his presen age is 6/5 times his age at the time of his marriage. kevin's sister was 10 years younger to him at the time of his marraige . The age of kevin's sister is
[A] 38
[C] 29
[B] 42
[D] 44

• given that kevin got married 8 years before say x years at the time of marriage
  means now the age is x+8
  and also given that now the is 6/5 times of his marriage
  i.e x+8=(6/5)x
  5x+40=6x
  x=40 this is at the time of marriage
  but at present the age is 40+8=48
  his sister is 10 years younger then his sister age is 48-10=38
  
• 10 years agoHelpfull: Yes(28) No(1)
• kevin,s sister age is 38 years.
• 10 years agoHelpfull: Yes(2) No(1)
• let the kelvin present agr be x
  8 year ago=x-8
  according to question
  x=6/58(x-8)
  5x=6x-48
  x=48
  kelvin sister's age duing marriage
  (48-8)-10
  =30
  present age of his sister30+8=38
• 10 years agoHelpfull: Yes(1) No(0)
• let kevins age be 'x' at the time of his marriage
  kevin got married 8 yrs ago his presen age is 6/5 times his age at the time of his marriage i.e.,x+8=(6/5)x ==>x=40
  kevins sister is 10 yrs younger than him so sister=x-10==>sister age at that time= 30
  so present age is 38
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• a =38 ans
  
• 10 years agoHelpfull: Yes(0) No(0)
• K=6*(K-8)/5
  k=48
  k=s+10
  s=38
• 6 years agoHelpfull: Yes(0) No(0)