A and B can do a piece of work in 18 days.B and C together can do it in 24 days. if A is twice as good a work man as C, find in what time B alone can do it.
[A] 36 days
[C] 16 days
[B] 11 days
[D] 20 days

• ans is 36 DAYS
  
• 10 years agoHelpfull: Yes(23) No(2)
• (A+B)'s 1 day work = 1/ 18 and A=2C. (B+C)'s 1 day work = 1/24 .
  
  Subtracting we get C's 1 day work = 1/72 and hence A=2C => A's 1 day work = 1/36.
  
  So B's 1 day = 1/36 - 1/18 = 1/36 . so B can do in 36 days
• 10 years agoHelpfull: Yes(17) No(0)
• a+b = 18 days,
  b+c = 24 days
  
  So, time required by b = 36 days.
• 10 years agoHelpfull: Yes(3) No(5)
• ans is 144 days
• 11 years agoHelpfull: Yes(1) No(20)