Smallest number having 2, 3, 5 and 7 as its multiple and divisible by 100 will be ?

• lcm of 2, 3, 5, 7 =210
  210*10=2100
  that is divisible by 100
  i think 2100 is the ans...
  
• 10 years agoHelpfull: Yes(3) No(0)
• Since it is divisible by 100,the number should be a multiple of 100.That implies it is a multiple of 2 and 5 automatically.Now since the number should also be a multiple of 3 and 7 . We have the lcm as 21.Therefore the smallest number=21*100=2100
• 9 years agoHelpfull: Yes(1) No(0)
• Smallest number having 2,3,5, and 7 as its multiple=210.
  but since the multiple should also be divisible by 100.
  So,
  answer=2100
• 9 years agoHelpfull: Yes(0) No(0)
• 2100
  it should have two zeroes , so it is definitely divisible by 2 and 5
  and it should divisible by 7 and 3
• 9 years agoHelpfull: Yes(0) No(0)
• having 2,3,5,7 as multiple => lcm=2*3*5*7=210
  it should be divisible by 10 => 210*10=2100
  therefore ans is 2100
• 9 years agoHelpfull: Yes(0) No(2)
• 3*7*100=2100 (as 100 has multiple of 2,5 both)
• 9 years agoHelpfull: Yes(0) No(0)
• 2357*100=235700
  2357/100=23.57
• 9 years agoHelpfull: Yes(0) No(3)
• lcm of 2,3,5,7 is 210
  210*100 = 21000
  i think 21000 is the answer.
• 9 years agoHelpfull: Yes(0) No(1)
• here the multiple of 2,3,5,7 is 210 but still it is not divisible without decimal by 100 so the number must 2100 now it can be devided by 100
• 9 years agoHelpfull: Yes(0) No(0)