Syntel Company Numerical Ability Time and Work

A cistern is normally filled by a tap in 5 hours, but suddenly a leak develops and it empties the full cistern in 30 hours. with the leak, the cistern is filled in
[A] 6 h
[C] 8 h
[B] 7 h
[D] 7 1/2 h

Read Solution (Total 3)

Work done by the tap and the leak in 1 hr=(1/5-1/30)=5/30=1/6
since 1/6 part is fill 1n 1hr
so 1 part is fill in 6hrs.
Ans:- 6hrs
11 years agoHelpfull: Yes(22) No(1)

cistern fill=5 hours
cistern empty from leak= 1/30
If both are active parallels= 6 hours.
10 years agoHelpfull: Yes(4) No(2)
(1/5 - 1/30)=1/6hr.
6hr
10 years agoHelpfull: Yes(2) No(0)

Syntel Other Question

A tap can fill a swimming pool in h hours. what part of the pool is filled in y hours?
[A] y-h
[C] y/h
[B] y+h
[D] h/y
A cistern is filled in 9 hours and it takes 10 hours when there is a leak in its bottom. if the cistern is full, in what time will the leak empty it ?
[A] 15 h
[C] 80 h
[B] 12 h
[D] 90 h