TCS
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Numerical Ability
Time Distance and Speed
A man jogs at 6 mph over a certain journey and walks over the same route at 4 mph. What is his average speed for the journey?
a) 2.4 mph (b) 4 mph (c) 4.8 mph (d) 5 mph
Read Solution (Total 6)
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- Ans:c)4.8 mph
Formula for calculating the avg speed for same distannce = 2xy/(x+y)where x= speed of forward one and y =speed of return one
Average Speed = 2(6)4/(6+4)
=24/5 =4.8mph - 14 years agoHelpfull: Yes(9) No(0)
- ans is c)4.8
take a harmonic means of these two speeds,to get average speed
thatis avg speed = (2*6*4)/(6+4)=48/10=4.8
- 14 years agoHelpfull: Yes(4) No(0)
- use the formula
(2*x*y)/(x+y)
so
(2*6*4)/(6+4) = 4.8 mph - 14 years agoHelpfull: Yes(3) No(0)
- let distance be x.....
so avg speed is total dist/total time= 2x/(x/6 + x/4 ) = 2/(1/6 + 1/4)= 4.8mph - 14 years agoHelpfull: Yes(3) No(0)
- 2*6*4/(6+4)=4.8
formula is 2xy/(x+y) - 14 years agoHelpfull: Yes(3) No(0)
- Answer is 4.8 mph
- 9 years agoHelpfull: Yes(0) No(0)
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