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X and Y live in a North-South parallel street. X travels 10 km towards North to reach the east-west street . Y travels 6 km towards south to reach the east –west street . X travels now 4km towards east and y travels 8km towards west and they met each other. What is the distance between x and y?
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- 20.77 km.
It’s an interesting question. The distance from X to his point of meeting Y is 10.77 km (approx.). The distance from Y to his point of meeting X is 10 km. Hence the distance between X and Y is 10.77 + 10 = 20.77 km. ( Use Pythagoras theorem) - 10 years agoHelpfull: Yes(0) No(0)
- Total distance traveled in north south direction combined is 10+16 = 16 km. Total distance traveled in east-west direction combined is 4+8 = 12 km. Applying Pythagoras theorem root (16^2+12^2) = 20 km which is the longest side that is diagonal distance.
- 5 years agoHelpfull: Yes(0) No(0)
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